The answer and just say the answer no links

Which of the following sequences shows a frameshift mutation compared to the wild-type mRNA sequence?

Butoxors [25]

Option C:

B. wild-type 5-AUGCAUACAUUGGAGUGA-3 mutant 5'-AUGCAUACAUCUGGAGUGA- 3'

Explanation:

A frameshift mutation is a genetic mutation such that the triplet nature of gene expression by codons, the insertion or deletion occurs in such as way that it alters the complete sequence of 3 codon sets and can change the reading frame, resulting in a completely different translation from the original.

As it is pertinent to understanding that all genes are normally translated in sets of 3 codons, which typically describes and explain a unique amino acid sequence. Thus, if a frame shift mutation occurs, it can affect many amino acid sequences and finally the entire protein.

If we look at option B:

wild-type 5-AUG CAU ACA UUG GAG UGA-3

mutant 5’- AUG CAU ACA UCU GGA GUG A-3’

An insertion of a base Uracil showed at the end of 3rd codon which affected and altered the whole sequence of codon triplets. This changed all next codons and finally all next amino acids will be altered.

8 0

3 years ago

Why are protozoa significant? Select all that apply. Protozoa contaminate the water supply. Protozoa do not contribute to a food

Luba_88 [7]

Answer: Protozoa contaminate the water supply.

Some protozoa are parasites and cause diseases like malaria.

Protozoa have an important role in the food chain.

Protozoa are parasitic or free living single celled eukaryotic organisms. They are mostly found in water bodies.

Protozoa contaminate the water supply: Some of the protozoan species which are released from the human feces usually contaminate thee water, and causes waterborne infections in humans. Examples are Cryptosporium and Giardia. The infection occurs through drinking water or swallowing water from swimming pool.

Some protozoa are parasites and cause diseases like malaria: The Plasmodium is the genus belonging to the protozoan parasites. This malarial parasite is transmitted by female Anopheles mosquitoes to humans. The parasite multiply in the red blood cells causes symptoms like fever, anemia, flue, illness and may also cause coma and death.

Protozoa have an important role in the food chain: The protozoa species plays many roles in the food chain, they act as consumers, predators or prey, herbivores and decomposers. Their main function is to control the population of other species in the same habitat. They engulf small single celled bacteria, hence prevents excessive bacterial colonization act as predator. They also feed upon the algal species therefore, act as herbivores. They act as decomposers, as they feed upon the organic matter present in the bottom of the aquatic water body. They are the source of food for large worm and insect species.

5 0

3 years ago

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A researcher is studying a newly discovered gene that causes increased body weight in domesticated chickens. In a mainland popul

Dima020 [189]

Answer:

0.382

Explanation:

In solving this, let's recall the Hardy-Weinberge's equations which are as follows: p + q = 1; $p^{2} + 2pq + q^{2} = 1$ , where p represents the dominant Allele, while q represents the recessive allele. In applying this to what we want to calculate, $p^{2} = A1A1$ , 2pq = A1A2, and $q^{2} = A2A2$ .

Using the Hardy-Weinberge's equations, we can determine the number of individuals having the different types of genotype inherent in the 100 mainland chicken that was transported.

Since p + q = 1, i.e. given that allele frequency of A1 is 0.2, therefore allele frequency for A2 = 0.8 (p + q = 1).

Using $p^{2} + 2pq + q^{2} = 1$ , we would have the following:

$p^{2} = A1A1 = 0.2^{2} = 0.04$

$2pq = A1A2 = 2(0.2*0.8) = 0.32$

$qx^{2} = A2A2 = 0.8^{2} = 0.64$

Therefore, number of mainland chickens with the A1A1 genotype = 0.04*100 = 4; A1A2 = 0.32*100 = 32; A2A2 =0.64*100 = 64

The genotype frequencies for the admixed population would be the sum of that of the transported mainland chicken and that of the isolated chicken, which would be:

Genotype mainland isolated Total No of A1 allele present

A1A1 4 200 204 204

A1A2 32 400 432 216

A2A2 64 400 464 0

Total 1100 420

Therefore, allele frequency of the A1 allele in the admixed population = 420/1100 = 0.382

4 0

3 years ago

I have no idea to label this.

musickatia [10]

Answer:

1.glomerulus

2.bowmans capsule

3.distal tubule

4. collecting duct

5. loop of henle

6.proximal tubule

Explanation:

Lucky for you you dont have to pull through this year with packets straight on nephrons and class assesments. UwU heres a link to a better diagram, thank me later

7 0

3 years ago

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What happens to the amount of water in the high plains aquifer over time

Art [367]

The temperature changes for sure depending on where it is.

4 0

3 years ago