Answer:
small=2, large=8
Step-by-step explanation:
let every candle holder(small) hold x candle and large y.
=>east side= 10x+4y=52-equation 1
=>west side=2x+4y=36-equation 2
equation 1 - equation 2=10x+4y-(2x+4y)=52-36
=>10x-4y-2x-4y=16
=>8x=16
=>x=16/8=2 candles
therefore, every small candle holder has 2 candles.
for large candle holders' capacity=> 2*2+4y=36
4+4y=36
4y=32
y=32/4=8 candles
Brainliest please
Answer:
2nd and 4th options
Step-by-step explanation:
4/5x - 1/5x + 3 = 3/5x + 3
1 + 3/5x + 2 = 3/5x + 3
Answer:
the length of missing side is 28
The problem uses the perimeter formula. P = 2w + 2l where w is the width, and l is the length.
We know the length (l) is 3 inches longer than it's width (or l = w+3). Substitute w +3 into Perimeter equation
P = 2w + 2(w+3). That simplifies to P = 4w + 6.
Since P + 42, we have 42 = 4w +6. With some simple algebra we find that w = 9 and l = 12.
Hope this helps!
