<span>Question :
The length of a side of a square is . If the area of the square is 12, find x.
Answer :
</span>
![area\ of\ the\ square = side \times side](https://tex.z-dn.net/?f=area%5C%20of%5C%20the%5C%20square%20%3D%20side%20%5Ctimes%20side)
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</span>
![12 = x \times x](https://tex.z-dn.net/?f=12%20%3D%20x%20%5Ctimes%20x)
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</span>
![12 = x^{2}](https://tex.z-dn.net/?f=12%20%3D%20x%5E%7B2%7D)
<span>
</span>
![x^{2}=12](https://tex.z-dn.net/?f=x%5E%7B2%7D%3D12)
<span>
</span>
![x= \sqrt{12}](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%7B12%7D%20)
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</span>
![x= \sqrt{4 \times 3}](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%7B4%20%5Ctimes%203%7D%20)
<span>
</span>
![x= 2\sqrt{3}](https://tex.z-dn.net/?f=x%3D%202%5Csqrt%7B3%7D%20)
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</span>
Answer:
The answers are :
1. 5%.
2. 467.50 DKK.
Step-by-step explanation:
Given:
Discount on Monday of a good at 10 percent.
Increase discount on Friday would be 15 percent.
1. Difference between the percentage =
.
So, the percentage increase in discount is
.
2. First, the actual price means the price without discount should be calculated.
So,let the actual price be
:
According to question,
of![x=495 DKK](https://tex.z-dn.net/?f=x%3D495%20DKK)
=![\frac{90x}{100}=495](https://tex.z-dn.net/?f=%5Cfrac%7B90x%7D%7B100%7D%3D495)
Multiplying both sides by 100
![\frac{90x}{100}\times100=495\times100](https://tex.z-dn.net/?f=%5Cfrac%7B90x%7D%7B100%7D%5Ctimes100%3D495%5Ctimes100)
=![90x=495](https://tex.z-dn.net/?f=90x%3D495)
Dividing both sides by 90
![\frac{90x}{90} =\frac{49500}{90}](https://tex.z-dn.net/?f=%5Cfrac%7B90x%7D%7B90%7D%20%3D%5Cfrac%7B49500%7D%7B90%7D)
=
.
And, now the price after the announcement of the
discount
of ![550](https://tex.z-dn.net/?f=550)
=
% of ![550](https://tex.z-dn.net/?f=550)
=![\frac{85}{100}\times550](https://tex.z-dn.net/?f=%5Cfrac%7B85%7D%7B100%7D%5Ctimes550)
=![\frac{46750}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B46750%7D%7B100%7D)
=
.
So, the price after the announcement of the
percent discount is
DKK.
Therefore, the answers are :
1. 5%.
2. 467.50 DKK.
Answer:
![D. (3,-1)](https://tex.z-dn.net/?f=D.%20%283%2C-1%29)
Step-by-step explanation:
![x + y = 2 \: \: \: \: \: \: ..(1) \\ 2x - y = 7 \: \: \: \: ..(2)](https://tex.z-dn.net/?f=x%20%2B%20y%20%3D%202%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20..%281%29%20%5C%5C%20%3C%2Fp%3E%3Cp%3E2x%20-%20y%20%3D%207%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20..%282%29)
from equation 1 we get,
![x = 2 - y](https://tex.z-dn.net/?f=x%20%3D%202%20-%20y)
now,
![put \: \: \: \: x = 2 - y \: \: \: in \: (2)](https://tex.z-dn.net/?f=put%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20x%20%3D%202%20-%20y%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20in%20%5C%3A%20%282%29)
we get,
![2(2 - y) - y = 7 \\ 4 - 2y - y = 7 \\ 4 - 3y = 7 \\ - 3y = 7 - 4 \\ - 3y = 3 \\ \\ y = \frac{3}{( - 3)} \\ \\ y = - 1](https://tex.z-dn.net/?f=2%282%20-%20y%29%20-%20y%20%3D%207%20%5C%5C%204%20-%202y%20-%20y%20%3D%207%20%5C%5C%204%20-%203y%20%3D%207%20%5C%5C%20%20-%203y%20%3D%207%20-%204%20%5C%5C%20%20-%203y%20%3D%203%20%20%5C%5C%20%20%5C%5C%20y%20%3D%20%20%5Cfrac%7B3%7D%7B%28%20-%203%29%7D%20%20%5C%5C%20%20%5C%5C%20y%20%3D%20%20-%201)
now,
![put \: \: \: \: y = - 1 \: \: \: \: in \: (1)](https://tex.z-dn.net/?f=put%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20y%20%3D%20%20-%201%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20in%20%5C%3A%20%281%29)
we get,
![x + ( - 1) = 2 \\ x - 1 = 2 \\ x = 2 + 1 \\ x = 3](https://tex.z-dn.net/?f=x%20%2B%20%28%20-%201%29%20%3D%202%20%5C%5C%20x%20-%201%20%3D%202%20%5C%5C%20x%20%3D%202%20%20%2B%201%20%5C%5C%20x%20%3D%203)
hence, the value of x = 3 and y = (-1)
Answer:
3x - 6
Step-by-step explanation:
Using the keywords "a number" and "few than" and "times" we can identify the expression.