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Goryan [66]
3 years ago
6

Does anyone know how he got from step 1 to step 2??????????

Mathematics
1 answer:
padilas [110]3 years ago
3 0

9514 1404 393

Explanation:

Both sides of the equation are squared.

  \dfrac{x-12}{4}=\sqrt{x} \qquad\text{given}\\\\ \left(\dfrac{x-12}{4}\right)^2=x \qquad\text{square both sides}\\\\ \left(\dfrac{x}{4}-3\right)^2=x \qquad\text{divide out the fraction}\\\\ \dfrac{x^2}{4^2}-\dfrac{6}{4}x+9=x \qquad\text{$(a-b)^2=a^2-2ab+b^2$}\\\\\dfrac{x^2}{16}-\dfrac{5x}{2}+9=0 \qquad\text{subtract $x$}

I like this better without fractions, so would multiply by 16 at this point (or earlier).

  x^2 -40x +144 = 0

  (x -36)(x -4) = 0

  x = 4 or 36 . . . . . . x = 4 is extraneous

The solution is x = 36.

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Answer:

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Data given

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\mu population mean (variable of interest)

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Part a: System of hypothesis

We need to conduct a hypothesis in order to determine if actual mean is different from 40 , the system of hypothesis would be:    

Null hypothesis:\mu =40      

Alternative hypothesis:\mu \neq 40      

Part b

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A Type of error I is reject the hypothesis that \mu is equal to 40 when is fact [tex]\mu is equal to 40

Part c

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