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seraphim [82]
4 years ago
13

I need help on this question!!

Mathematics
1 answer:
Anastasy [175]4 years ago
4 0
There are 10 values in the data set. Conveniently, they are sorted for you. The median (central line in the box) will be the average of the middle two numbers:
.. (20 +22)/2 = 21 . . . . . . . . matches the 2nd and 4th selections

The first quartile (the left end of the box) will be the middle number of the first group of 5, so is 9. This matches the 4th selection only.

The 4th selection is appropriate.
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X − 3 − 2(6 − 2x) = 2(2x − 5)
Finger [1]

Multiply the first bracket by -2

Multiply the second bracket by 2

x-3-12+4x= 4x-10

- negative number times + positive number= - negative number

- negative number times -negative number = + positive number

x+ 4x-3-12= 4x-10

5x-15= 4x-10

Move 4x to the other side

5x-4x-15= 4x-4x-10

x-15= -10

Move -15 to the other side

x-15+15= -10+15

x= 5

Answer : x= 5

7 0
3 years ago
Read 2 more answers
Determine if each relationship is a proportional or nonproportional Explain your reasoning. The problem is, v= 1/10u
timama [110]
Hello hey hii baby girl
6 0
3 years ago
What two numbers' sum=-4 and product=-2
n200080 [17]

Let <em>a</em> and <em>b</em> be the two numbers. Then

<em>a</em> + <em>b</em> = -4

<em>a b</em> = -2

Solve the second equation for <em>b</em> :

<em>b</em> = -2/<em>a</em>

Substitute this into the first equation:

<em>a</em> - 2/<em>a</em> = -4

Multiply both sides by <em>a</em> :

<em>a</em>² - 2 = -4<em>a</em>

Move 4<em>a</em> to the left side:

<em>a</em>² + 4<em>a</em> - 2 = 0

Use the quadratic formula to solve for <em>a</em> :

<em>a</em> = (-4 ± √(4² - 4(-2))) / 2

<em>a</em> = -2 ± √6

If <em>a</em> = -2 + √6, then

-2 + √6 + <em>b</em> = -4

<em>b</em> = -2 - √6

In the other case, we end up with the same numbers, but <em>a</em> and <em>b</em> are swapped.

7 0
3 years ago
(10.02)
melisa1 [442]

Answer:

sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}

Therefore:

sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}

cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}

Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}

4 0
3 years ago
Determine whether the following graph represents a function.
4vir4ik [10]

Answer:

function

Step-by-step explanation:

8 0
3 years ago
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