Question

Help please!

Answer 1

Step-by-step explanation:

you're just going to switch x and y and then solve for y

Answer 2

Answer:

Hello,

Step-by-step explanation:

The problem is that the inverse function is not a function but

an union of 2 functions.

$y=(x+6)^2+1\ is\ the\ orignal\ function\ f(x).\\\\Inverting\ x\ and\ y\ gives: \ x=(y+6)^2+1\\\\(y+6)^2=x-1 \ nota\ bene\ x-1\geq 0 \\(y+6)^2-(x-1)=0\\\\((y+6)-\sqrt{x-1} ) * ((y+6)+\sqrt{x-1}) =0\\\\y=-6+\sqrt{x-1}-6\ or\ y=-6-\sqrt{x-1}$

For the fun

,$f_1(x)= (x+6)^2+1=0\ if\ x$