You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
Answer:
<em><u>Answer is below</u></em>
Step-by-step explanation:
<u><em>3+5(2−3)−6</em></u>
<u><em>=3+(5)(−1)−6</em></u>
<u><em>=3+−5−6</em></u>
<u><em>=3+−11</em></u>
<u><em>=−8</em></u>
<u><em>So therefore, your answer would be -8</em></u>
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The line y = 8x passes through the origin, which is the point (0, 0).
We say the ordered pair (0, 0) lies on the graph y = 8x.
3*7-6
21-6=15
15 is the answer
