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Natali [406]
2 years ago
14

A 6 foot tall football player casts a 16 inch shadow at the same time stadium we discussed at six for shadow how tall the bleach

ers
Mathematics
1 answer:
katrin [286]2 years ago
5 0
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.

6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.

So the bleachers are 9/2 x 6 ft = 27 ft.

For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.

So the stage will have dimensions 216 times larger than 1.75" by 3".

That would be 31ft 6ins x 54ft.

Live long and prosper.
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The heights of some students are given 158cm 171cm 164cm 164cm 167cm 159cm what is the range of the heights?
bogdanovich [222]

Answer:

The range of students is 13.

Step-by-step explanation:

Take the largest number and subtract it from the smallest number. For example, 171 - 158 = 13 cm.

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3 years ago
The exponent of 2√9 is
AVprozaik [17]

Answer:

the exponent is 6............

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2 years ago
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zimovet [89]

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2 years ago
Picture says all 20 charecters needed
Alika [10]

Answers:

Lower bound = 41.3

Upper bound = 41.5

===========================================================

Explanation:

49.15 is the smallest f can be while 49.24 is the largest it can be. Well technically we could have something like 49.2499 or 49.24999 and so on. We slowly approach 49.25 but never actually get there

So the variable f is between 49.15 and 49.25 inclusive of the first value but excluding the second value. We can write it as 49.15 \le f < 49.25

For similar reasoning, 7.75 \le g < 7.85

-----------------

If we wanted to subtract those variables and get the smallest result possible, then we need to pick values that are closest together. It might help to set up a number line.

This means we'd go for f = 49.15 and g = 7.85

The lower bound for f-g is f-g = 49.15-7.85 = 41.3

In contrast, the upper bound is when the two variables are spaced as far apart as possible. The upper bound is f-g = 49.25 - 7.75 = 41.5

7 0
1 year ago
Read 2 more answers
If a quadratic equation has a discriminant that equals zero, which of the following statements is always true?
kotegsom [21]

Answer:

d. The equation has one solution and there is not enough information to determine the direction of the parabola.

Step-by-step explanation:

For a general quadratic equation

y = ax² +bx +c

the solution is

x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

The discriminant (D) is the part of the quadratic formula underneath the radical: b² - 4ac.

D tells us whether there are

  • two different real solutions
  • two identical real solutions ("one solution")
  • two complex solutions.

If D= 0,

x = \dfrac{-b}{2a}\pm0 = \mathbf{\dfrac{-b}{2a}}

and there are two identical solutions ("one solution").

The direction of the parabola depends on the sign of a.

That information is not given, so we cannot determine the direction of the parabola.

7 0
3 years ago
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