Midpoint of JN is at coordinates (3,2)
Step-by-step explanation:
Coordinates of j= (10,-2)
Coordinates of N = (-4,6)
We need to find midpoint of JN.
The formula used to find midpoint is:
![Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})](https://tex.z-dn.net/?f=Midpoint%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%29)
We are given:
![x_1=10,x_2=-4,y_1=-2,y_2=6](https://tex.z-dn.net/?f=x_1%3D10%2Cx_2%3D-4%2Cy_1%3D-2%2Cy_2%3D6)
Putting values and finding midpoint of JN
![Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})](https://tex.z-dn.net/?f=Midpoint%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%29)
![Midpoint=(\frac{10-4}{2},\frac{-2+6}{2})](https://tex.z-dn.net/?f=Midpoint%3D%28%5Cfrac%7B10-4%7D%7B2%7D%2C%5Cfrac%7B-2%2B6%7D%7B2%7D%29)
![Midpoint=(\frac{6}{2},\frac{4}{2})](https://tex.z-dn.net/?f=Midpoint%3D%28%5Cfrac%7B6%7D%7B2%7D%2C%5Cfrac%7B4%7D%7B2%7D%29)
![Midpoint=(3,2)](https://tex.z-dn.net/?f=Midpoint%3D%283%2C2%29)
So, midpoint of JN is at coordinates (3,2)
Keywords: Midpoint of line
Learn more about Midpoint of line at:
#learnwithBrainly
Answer:
27
Step-by-step explanation:
First, find the volumes of each figure.
Remember that the volume of a sphere =
![\frac{4}{3} \pi r^3](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E3)
Smaller sphere:
![\frac{4}{3}\pi*10^3](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%2A10%5E3%20)
4188.79 Cubic inches.
Larger sphere:
![\frac{4}{3}\pi*20^3](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%2A20%5E3)
33510.32 Cubic inches.
33510.32 - 4188.79 = 29321.53 cubic inches
Hope that helps!
thank me the answer is x=3.6