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2 years ago

12

I need help on this one please :)

1 answer:

madreJ [45]2 years ago

3 0

Line DE is 4 squares and Line BC is 8 squares.

The length of line DE is 1/2 of line BC

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4x=2 solve for X<br><img src="https://tex.z-dn.net/?f=4x%20%3D%202%20solve%20for%20x" id="TexFormula1" title="4x = 2 solve for x

Bogdan [553]

X=1/2 hope this helps <3

3 0

2 years ago

Read 2 more answers

16a, b, c, and 18a, b, c

Oliga [24]

I can answer 18 for you, but I don't understand 16

18. Since when we lose 3 girls the ratio for the girls side drops by 1, that tells us that 1 digit equals 3 people.

a) 5*3=15 so our answer is 15 girls.

b) 4*3=12 and 5*3=15 so 15+12, our answer would be 27

7 0

2 years ago

Generate the nest three terms of each arithmetic sequence shown below.

o-na [289]

Answer:

A)2,6,10

B)2,-6,-18

C)-1,-3,-5

Step-by-step explanation:

<u>A)a1=-2 and d=4</u>

We know that the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{2}=a_{1}+(2-1)d$

$a_{2}=a_{1}+(1)d$

Substituting the given value we get

$a_{2}= -2+(1)4$

$a_{2}= -2+4$

$a_{2}= 2$

------------------------------------------

Similarly

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the given value we get

$a_{3}= -2+(2)4$

$a_{3}= -2+8$

$a_{3}= 6$

-------------------------------------------------

$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the given value we get

$a_{4}= -2+(3)4$

$a_{4}= -2+16$

$a_{4}= 10$

-------------------------------------------------------------------------------------------

<u>B</u><u> $a_n=a_{(n-1)}-8$ with $a_1=10$ </u>

$a_2=a_{(2-1)}-8$

$a_2=a_{1}-8$

Substituting the given value

$a_2= 10-8$

$a_2=2$

---------------------------------------------------------------------

$a_3=a_{(3-1)}-8$

$a_3=a_{2}-8$

Substituting the value

$a_3=2-8$

$a_3= -6$

---------------------------------------------------------------------

$a_4=a_{(4-1)}-8$

$a_4=a_{3}-8$

Substituting the value

$a_4= -6-8$

$a_4= -14$

-------------------------------------------------------------------------------------------

<u>C) $a_1=3, a_2=1$ </u>

Here the difference is -2

the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the value we get

$a_{3}= 3+(2)-2$

$a_{3}= 3-4$

$a_{3}= -1$

------------------------------------------------------------------------------

$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the value we get

$a_{4}= 3+(3)-2$

$a_{4}= 3-6$

$a_{4}= -3$

----------------------------------------------------------------------------------

$a_{5}=a_{1}+(5-1)d$

$a_{5}=a_{1}+(4)d$

Substituting the value we get

$a_{5}= 3+(4)-2$

$a_{5}= 3-8$

$a_{5}= -5$

4 0

2 years ago

Trig help please!!! This is due tomorrow. If you don’t mind could you please explain how you do it

vivado [14]

Answer:

The larger acute angle is equal to 50.8 degrees.

Step-by-step explanation:

Let's solve for both of the acute angles for the purpose of checking our work at the end with angle A being the top angle and angle B being the one on the base of the triangle (that's not the 90 degrees one). Determining whether to use sin/cos/tan comes from SOH-CAH-TOA.

A = cos^-1 (2√6/2√15)

However, you need to move the radical out of the denominator by multiplying √15 to the numerator and denominator. You should come up with (2√90)/30. So,

A = cos^-1 (2√90/30) = 50.768 degrees.

B = sin^-1 (2√90/30) = 39.231 degrees.

Now, we can check the work by adding the 2 angles to 90 and, if it comes to 180, it's right.

cos^-1 (2√90/30) + sin^-1 (2√90/30) + 90 = 180.

If you have any questions on where I got a formula or any step, feel free to ask in the comments!

8 0

2 years ago

What is 40% of 1000 in need to know some help

loris [4]

The answer would be 400

3 0

2 years ago

Read 2 more answers