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valkas [14]
3 years ago
13

A cylinder has a radius of 10m and a height of 8m. What is the exact volume of the cylinder?

Mathematics
1 answer:
AveGali [126]3 years ago
5 0
Since the cylinder has a radius of 10m and a height of 8m, then the exact volume would be 800^m3

The correct option among the other answer choices would be as follows: D.

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Mrs. Duran ordered a used book online. She paid a total of $5.65 for the book and shipping. The cost of the book alone was $3.31
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A rectangle has vertices at these coordinates. (2, −2), (2, 5), (−1, 5) What are the coordinates of the fourth vertex of the rec
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(-1,-2) That is the answer to your question.

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Frações Algébricas - 3* caso <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B1%7D%7B2x-4%7D%20%20%2B%20%5Cfrac%7Bx-1%7D%7B3x-6%7
Ulleksa [173]

Answer:

\dfrac{5x + 1}{6(x - 2)}

\dfrac{5x + 1}{6x - 12}

Step-by-step explanation:

Fatorizam-se os denominadores.

2x - 4 = 2(x - 2)

3x - 6 = 3(x - 2)

O minimo multiplo comum dos denominadores e

2(3)(x - 2)

\dfrac{x + 1}{2x - 4} + \dfrac{x - 1}{3x - 6} =

= \dfrac{3(x + 1)}{2(3)(x - 2)} + \dfrac{2(x - 1)}{2(3)(x - 2)}

= \dfrac{3(x + 1) + 2(x - 1)}{6(x - 2)}

= \dfrac{3x + 3 + 2x - 2)}{6(x - 2)}

= \dfrac{5x + 1}{6(x - 2)}

= \dfrac{5x + 1}{6x - 12}

4 0
2 years ago
The graph and the equation show the relationship between gas price and amount of gas purchased for two different stations. Which
AlladinOne [14]

Answer:

Step-by-step explanation:

The answer is B

5 0
2 years ago
Read 2 more answers
The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand
Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})

P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})

P(X > 1560) = P(Z > \dfrac{110}{220})

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean \mu_x = np = 52 × 0.3085 = 16.042

The standard deviation =  \sqrt {n \time p (1-p)}

The standard deviation = \sqrt {52 \times 0.3085 (1-0.3085)}

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})

Pr ( Y > 20) = P(Z >1 .338)

From z tables

P(Y > 20) \simeq 0.0903

7 0
3 years ago
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