Question

Consider the equation 4•e^2.7x = 33

Answer 1

Answer:

$\huge x = ln( \frac{33}{4} ) \times \frac{ 10}{27} \\ \huge \: x \approx 0.782$

Step-by-step explanation:

to understand this

you need to know about:

• logarithm
• PEMDAS

let's solve:

$4 {e}^{2.7x} = 33 \\ {e}^{2.7x} = \frac{33}{4} \\ 2.7x = ln( \frac{33}{4} ) \\ x = ln( \frac{33}{4} ) \times \frac{ 10}{27} \\ x \approx 0.782$