We know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem)
Let
A------> Lincoln, NE
B------> Boulder, CO
C------> third city
we know that
in the triangle ABC
AB=500 miles
BC=200 miles
AC=x
Applying the Triangle Inequality Theorem
1) 500+200 > x------> 700 > x------> x < 700 miles
2) 200+x > 500----> x > 500-200------> x > 300 miles
the solution for x is
300 < x < 700
the interval is------> (300,700)
the possible distances, d, in miles, between Lincoln, NE, and the third city, are in the range between 300 and 700 miles
Answer:
the snapshot is how you graph y= -2 x + 10
Step-by-step explanation:
brainliest?
Answer: Down below
Step-by-step explanation:=(600-250)m=350m
i think the answer is 8 dogs and 7 cats 15 in total
Answer:
r = -8/5
Step-by-step explanation:
-7 log4 (-10r) = -14
Divide each side by -7
-7/-7 log4 (-10r) = -14/-7
log4 (-10r) = 2
Raise each side to the base of 4
4^ log4 (-10r) = 4^2
-10r = 16
Divide each side by -10
-10r/-10 = 16/-10
r = -116/10
r = -8/5
