Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
4/AC = AC/9
AC ^2 = 36
AC = 6
The figures that can match are those which are similiar in shape.
Observe that polygons 1 and 4 have similar shape, hence those are the answer.
<h2>A is the answer.</h2>
Answer:
t > 82
Step-by-step explanation:
First write what we know.
Earned $72
$4 per ticket, t
Cost is $400
So let's write our equation:
The cost is $400 so we put that on the left side,
$400 =
Now on the right side, we know they earned $72, so +$72 and each ticket (t) is $4 so $4t would represent the amount earned after they sell a certain number of tickets.
So we write:
$400 = $4t + $72 Now solve for t to find the number of tickets they need to sell.
400 = 4t + 72 Subtract 72 from each side.
400 - 72 = 4t + 72 - 72
328 = 4t Divide each side by 4.
328/4 = 4t/4
328/4 = t
82 = t
If the committee wants money left over they need to sell more than 82 tickets!
Our inequality is:
t > 82
Answer:
Ok ill try to answer
Step-by-step explanation:
