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Thepotemich [5.8K]
3 years ago
8

John bought 4 pounds of hot dogs for his party.

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
3 0

Answer:

64

Step-by-step explanation:If 1 pund is 16 oc times that by 4 and you get 64

Aneli [31]3 years ago
3 0

Answer:

64

Step-by-step explanation:

we would just multiply 16 by 4 and get 64

can i get brainliest

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A square is of length 15cm and area of 225cm² find its breadth ​
siniylev [52]

Answer:

15

Step-by-step explanation:

Pls find attached picture

3 0
4 years ago
Read 2 more answers
Ms. Moneyhun's son, Sam, just learned to crawl. He can crawl 20 ft in one minute. How many feet can Sam crawl in one hour? (Hint
almond37 [142]

Answer:

1200 ft in one hour

Step-by-step explanation:

The ratio of Sam crawling 20 ft in one minute can be written as:

20:1

Multiply the ratio by 60 to get the minutes to 60 minutes, because there are 60 minutes in an hour:

 20    :    1

×60     ×60

To get:

1200:60  ⇒  This means Sam can crawl 1200 ft in 60 minutes, which is the same as 1200 ft in one hour.

<em>Hope this helps!</em> :)

6 0
3 years ago
You are buying a $14.95 item that has 4.5% sales tax. You give the cashier a $20 bill. How much change do you get back?
Inessa [10]
The answer is $16.64.

4 0
3 years ago
Read 2 more answers
What is the answer...
klemol [59]

Answer:

64

Step-by-step explanation:

5x-16+6x=10x (combine like terms)

11x-16=10x (subtract 11x)

-16= -1x (divide by -1

16 = x

Now plug 16 into 5x-16.

5(16)-16 = 80-16 = 64

6 0
3 years ago
Determine
mihalych1998 [28]

Answer:

=4.+2.

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector \vec b is a linear combination of \vec a_1 and \vec a_2 if there are two scalars x_1, x_2 such as

\vec b=x_1\vec a_1+x_2\vec a_2

In our case, all the vectors are given in R^3 but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

We have

\vec a_1=,\ \vec a2=,\ \vec b=

We set the equation

=x_1.+x_2.

Multiplying both scalars by the vectors

=+

Equating each coordinate, we get

4x_1-4x_2=8

5x_1+3x_2=26

-4x_1+3x_2=-10

Adding the first and the third equations:

-x_2=-2

x_2=2

Replacing in the first equation

4x_1-4(2)=8

4x_1=8+8

x_1=4

We must test if those values make the second equation become an identity

5(4)+3(2)=20+6=26

The second equation complies with the values of x_1 and x_2, so the solution is

=4.+2.

8 0
3 years ago
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