Complete Question
A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:
a)F minimum
b) F maximum
c) Frequency resolution
Answer:
a) 
b) 
c) 
Step-by-step explanation:
From the question we are told that:
Time 
Frequency
Segments 
Generally the equation for Frequency Range is mathematically given by


Therefore
a) 
b) 
c)
Generally the equation for Frequency Resolution is mathematically given by

Where
N=The Total dat points
N=Sampling Frequency *Time


Therefore


The answer to the problem is 12. 2 times 3 is 6. 18 divided by 6 is 3 and 3 times 4 is 12.
2x(x+4)-1(x+4)
2x^2+8x-x-4
2x^2+7x-4
Answer:
y=−x+573, x+y=573
Step-by-step explanation:
This can be written as:
a+27=4(15-a)
now to work it out
a+27=4(15-a)
a+27=60-4a
4a+27=60
4a=33
a=8.25
<span>hope this helps :)</span>