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ANEK [815]
3 years ago
8

Which line represents a proportional relationship?

Mathematics
1 answer:
GREYUIT [131]3 years ago
4 0
The yellow one is the answer

Explaintion: Proportional relationships are relationships between two variables where their ratios are equivalent.

Heres an example of a proportional relationship on a graph:
The top is non proportional and the bottom is a proportional relationship

You might be interested in
Can you divide 25 into 4 equal groups? Explain why or why not.
alexira [117]

Answer:

No, not really.

dividing 25 into 4 equal groups, equals 6.25.

So no, you can not divide 25 into 4 equal group.

If if was 25 into 5 equal groups, then yes.

Hope this helps!!!

Please mark brainliest, if this helps. :)

Step-by-step explanation:

8 0
3 years ago
A box contains 5 purple marbles, 3 green marbles and 2 orange marbles. You draw the first marble, return it to the box and draw
GrogVix [38]

Answer:

1/15

Step-by-step explanation:

1/5+3+2        all of the marbles

2/10              odds of drawing an orange marble(bc 2 orange marble)

3/9                 because to get 3 green and 1 marble is removed and 9 is total          marbles left

2/10*3/9=1/15  muliply  odds because 2 draws of marbles    

6 0
3 years ago
PLEASE HELP ME I DONT UNDERSTAND.
Bingel [31]

width = 7cm

Length= 41cm

width=x

length=3x+20

96=3x+20+3x+20+x+x

96=8x+40

56=8x

x=8


5 0
3 years ago
Read 2 more answers
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
|3 - 5 + 7|.<br><br>O 15<br>O 5<br>O -15<br>O -5​
Aliun [14]

Answer:

5

Step-by-step explanation:

The answer is 5

because 3 - 5 = -2

and -2 + 7 = 5

so the answer is 5

4 0
3 years ago
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