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blagie [28]
3 years ago
15

What is the awnser to this question (w2x−3)÷10·z when w=−4, x = 0.8, and z=−45 k12

Mathematics
1 answer:
inn [45]3 years ago
6 0
42.3
(-4x2x0.8-3)=-9.4
-9.4/10=-0.94
-0.94x-45=42.3
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According to the values in the table, do x and y have a proportional relationship?
Masteriza [31]

Answer:

Yes.

Step-by-step explanation:

0.4 x 100 = 40

0.5 x 100 = 50

0.6 x 100 = 60

1 x 100 = 100

Hope this helped!

6 0
3 years ago
Which shows the correct substitution of the values a, b, and c from the equation 1 = –2x + 3x2 + 1 into the quadratic formula? Q
Tanzania [10]

First of all, you have to manipulate the equation into the standard

ax^2+bx+c=0

form. You can simplify the 1's on both sides and you have

3x^2-2x=0

This means that your coefficients are

a=3,\quad b=-2,\quad c=0

And since the solving formula is

x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

Plugging your values yields

x_{1,2}=\dfrac{-(-2)\pm\sqrt{(-2)^2-4\cdot 3\cdot 0}}{2\cdot 3}

5 0
3 years ago
Read 2 more answers
Hi! does anyone know how to solve this problem?
masha68 [24]

Answer:-5

Step-by-step explanation:

3 0
2 years ago
A system of equations is shown.
siniylev [52]
4x+20=5y
Divide 5 on both sides
so your answer would be 
4/5x+4=y

x+15=3y
Divide 3 on both sides 
so your answer would be
3x+5=y


6 0
3 years ago
More help, im still confused
nevsk [136]

Answer:

a) \frac{1}{3}

b) \frac{4}{5}

Step-by-step explanation:

a) the exponent is 2, therefore the value of \sqrt[2]{9} would go in the place of the base.

b) the exponent is 2, therefore the value of \sqrt[2]{\frac{16}{25} } would go in the place of the base => \frac{\sqrt{16}}{\sqrt{25}} = \frac{4}{5}

3 0
3 years ago
Read 2 more answers
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