3 years ago

I literally have no idea how to do this. Plz help. Bots will be taken down.

Mathematics

1 answer:

Nutka1998 [239]3 years ago

5 0

Answer:

Example 1: 48

Example 2: 15

Example 3: 26

Example 4: 37

Step-by-step explanation:

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If a number is divisible by both 2 and 3 then we can say the number is divisible by A. 5. B. 2. C. 4. D. 6.

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I believe it is d 6. you can divide 6 by both 3 and 2.

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2 years ago

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the sum of three numbers is 131. the third number is 4 times the first. the second number is 5 more than the first. what are the

Sphinxa [80]

Step-by-step explanation:

let the numbers are:

a, b, and c

the equation would be:

a+b+c = 131

c = 4a

b = a+5

a + a+5 +4a = 131

6a +5 = 131

6a = 131-5

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2 years ago

2. Find the common difference and the recursive formula. a. 22, 19, 16, 13, …

Musya8 [376]

Answer:

The common difference d is d = -3

The recursive formula is: $\mathbf{a_n=a_{n-1}-3}$

Step-by-step explanation:

We need to find the common difference and the recursive formula.

a. 22, 19, 16, 13, …

First we will find common difference

The formula of arithmetic sequence is: $a_n=a_1+(n-1)d$

where a_n is nth term, a_1 is 1st term and d is the difference

Looking at the sequence we get: a_1=22, a_2=19

Using these values we can find d, the common difference

$a_n=a_1+(n-1)d\\put\:n=2, a_2=19, a_1=22\\19=22+(2-1)d\\19=22+d\\d=19-22\\d=-3$

So, the common difference d is d = -3

Now, we will find the recursive formula:

The recursive formula is of type: $a_n=a_{n-1}+d$

We have found common difference d = -3

So, the recursive formula will be:

$a_n=a_{n-1}+d\\a_n=a_{n-1}+(-3)\\a_n=a_{n-1}-3$

The recursive formula is: $\mathbf{a_n=a_{n-1}-3}$

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3 years ago

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Lelu [443]

8-6=2 n=0 your very welcome!

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2 years ago