In order to answer the above question, you should know the general rule to solve these questions.
The general rule states that there are 2ⁿ subsets of a set with n number of elements and we can use the logarithmic function to get the required number of bits.
That is:
log₂(2ⁿ) = n number of <span>bits
</span>
a). <span>What is the minimum number of bits required to store each binary string of length 50?
</span>
Answer: In this situation, we have n = 50. Therefore, 2⁵⁰ binary strings of length 50 are there and so it would require:
log₂(2⁵⁰) <span>= 50 bits.
b). </span><span>what is the minimum number of bits required to store each number with 9 base of ten digits?
</span>
Answer: In this situation, we have n = 50. Therefore, 10⁹ numbers with 9 base ten digits are there and so it would require:
log2(109)= 29.89
<span> = 30 bits. (rounded to the nearest whole #)
c). </span><span>what is the minimum number of bits required to store each length 10 fixed-density binary string with 4 ones?
</span>
Answer: There is (10,4) length 10 fixed density binary strings with 4 ones and
so it would require:
log₂(10,4)=log₂(210) = 7.7
= 8 bits. (rounded to the nearest whole #)
Answer:
yeah she is
in y = m*x + <u>b
</u>
b is the initial value or the y-intercept.
Step-by-step explanation:
Answer:
132 teaspoons in a 22 ounce can
Step-by-step explanation:
There are 6 teaspoons in 1 ounce
22 * 6 = 132
The 9 combinations that exist for two movements:
R,R
R,L
R,U *
L,R
L,L
L,U
U,R *
U,L
U,U
Walker would only be able to make it to (1,1) with only 2 of these combinations.
So if he were only allowed to make two movements, his chances of arriving at (1,1) would be 2/9.
ANSWER
Given
The equation is
The equation of a rectangular hyperbola is xy = c²
where c is constant
thus above is the equation of the rectangular hyperbola.
First case
the graph of this equation is shown below.
Second case
is reflected over the y -axis
than the equation becomes
the graph is shown below.
Third Case
translated down 2 units to form f(x)
than the equation becomes
The graph is shown below.
