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schepotkina [342]
4 years ago
10

Can I get people that are actually willing to try instead of stealing points jeez.

Mathematics
2 answers:
Solnce55 [7]4 years ago
6 0

Answer:

I think the length of ED should be 6

velikii [3]4 years ago
4 0

THEOREM:

<u>Chord intersecting theorem</u> —» It states that the products of the lengths of the line segments on each chord are equal.

  • a × b = c × d

ANSWER:

Let ED be x. By chord theorem,

6 × x = 4 × 9

6x = 36

x = 6.

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Heyy i need help pls :(
elixir [45]

Answer:

First one  x = 14

Step-by-step explanation:

First one

The sum of the interior angles of a triangle = 180

so

(180-124)   +  (180-6x)   +  2x = 180

x = 14

4 0
2 years ago
Read 2 more answers
Anyone know the answer?
horrorfan [7]
I think they down graded it by 1080.Hope this helps. :)
5 0
3 years ago
Read 2 more answers
NEED HELP ASAP PLEASE
Lana71 [14]
 2x+4 + 10 = 3x + 1
2x - 3x = 1 - 13
-x = -13
x = 13
AC = 2(13) + 4 + 10 = 26 + 14 = 40

answer
<span>a. 40</span>

5 0
4 years ago
Answer number 16 please thank you
dusya [7]
I think the answer is B
7 0
3 years ago
47. Forming a Committee Four members from a 20-person committee are to be selected randomly to serve as chair- person, vice-chai
Svetllana [295]

Answer:

116,280 different leadership structures are possible

Step-by-step explanation:

The order is important.

For example, a Committee of John, Elisa, Laura and Rose means that John is the chairperson, Elisa the vice-chairperson, Laura the secretary and Rose the treasurer. If we exchange John and Elisa, their roles are also exchanged. This means that we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

How many different leadership structures are possible

Permutations of 4 elements from a set of 20. So

P_{(20,4)} = \frac{20!}{(20-4)!} = 116280

116,280 different leadership structures are possible

6 0
3 years ago
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