Answer:

Step-by-step explanation:
<u>Fundamental Theorem of Calculus</u>

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a <u>constant of integration</u>.

Increase the power by 1, then divide by the new power.
Given <u>indefinite integral</u>:

To integrate the given integral, use Integration by Parts:



Therefore:

Learn more about integration here:
brainly.com/question/27805589
brainly.com/question/27983581
brainly.com/question/27759474
S·S=500. S²=500. S=√500. S=22.36. 22.4 inches for 1 side, 22.4(4)=89.6, 89.6 for all 4 :)
Answer:
see explanation
Step-by-step explanation:
The n th term of an arithmetic progression is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given
= 12 and
= 22, then
a₁ + 5d = 12 → (1)
a₁ + 7d = 22 → (2)
Subtract (1) from (2) term by term to eliminate a₁
2d = 10 ( divide both sides by 2 )
d = 5
Substitute d = 5 into (1) to find a₁
a₁ + 5(5) = 12
a₁ + 25 = 12 ( subtract 25 from both sides )
a₁ = - 13
Thus
= - 13 + 5 = - 8
= - 13 + 5(n - 1) = - 13 + 5n - 5 = 5n - 18 ← n th term
Step-by-step explanation:
area of a circle
A = pi x r^2
r=9
The value is 4 because 4b is also 4 times three which is twelve then you divide 12 by three and get 4