Answer:
2a times the sq root of 2a or 2a (2a)**1/2
Step-by-step explanation:
(8a**3)**1/2 =
((2**2 * 2) (a**2) (a))**1/2 then take out and squares
2a (2a)**1/2
or 2a times the sq root of 2a
Answer:
The probability is 
Step-by-step explanation:
If she has n distinct password candidates and only one of which will successfully log her into a secure system, the probability that her first first successful login will be on her k-th try is:
If k=1

Because, in her first try she has n possibles options and just one give her a successful login.
If k=2

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and 1 of that give her a successful login.
If k=3

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and n-2 that are not correct and after that, she has n-2 possibles options and 1 give her a successful login.
Finally, no matter what is the value of k, the probability that her first successful login will be (exactly) on her k-th try is 1/n
I don’t have a double number line but she would have to spend 9.5 (9 1/2) hours babysitting to earn enough money to buy the dress
Answer:
True, based on the <em>Transitive Property of Equality</em>.
Step-by-step explanation:
Note that the <em>Transitive Property of Equality </em>states that "If a = b, & b = c, then a = c.
In this case it is the same.
∠1 ≅ ∠2 (because both are complementary), ∠1 ≅ ∠3 (again, both are complementary), then based on the Transitive Property, ∠2 ≅ ∠3, making all of them complementary angles
------------------------------------------------------------------------------------------------------
<em>~Senpai</em>
32 is the correct answer I believe if using PEMDAS method