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Svet_ta [14]
3 years ago
8

A.

Mathematics
1 answer:
Nina [5.8K]3 years ago
8 0
Between 8:30 and 6:30 is 10 hours. That is 600 minutes which is 36000 seconds. So you would do 600•2= 1200 and then do 36000-1200=34800 seconds. 34800/60=580 minutes so you would then take 540/60=9 which would make the time 5:30 p.m. but there is 40 minutes left over so it would end up being 6:10 p.m. lol I hope this is right because it took me forever
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I really need help pls. Its about 3d shapes
Svet_ta [14]

The image is blurry

Step-by-step explanation:

3 0
3 years ago
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Add 5x+4y;3x-7y;-4x+8y​
viktelen [127]

The answer is 4x + 5y.

Here, what needs to be done is to combine like terms.

  • 5x + 4y + 3x - 7y - 4x + 8y
  • 5x + 3x - 4x + 4y + 8y - 7y
  • 4x + 5y
4 0
2 years ago
I NEED HELP WITH THIS (GEOMETRY)
denis23 [38]

Answer:

x=30

Step-by-step explanation:

5x+x=180

6x=180

x=30

5x=150

x=30

3x=90

2x=60

5 0
4 years ago
Which table represents a linear functionWhich table represents a linear function
IceJOKER [234]

The table that has a constant average rate of change represents a linear function.

<h3>What is the average rate of change of a function?</h3>

The average rate of change of a function is given by the <u>change in the output of the function divided by the change in the input</u>.

When this rate is constant, the function is said to be linear, hence the table that has a constant average rate of change represents a linear function.

More can be learned about linear functions at brainly.com/question/24808124

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6 0
2 years ago
Question 3 (1 point) Co-60 has a half life of 5.3 years. If a pellet that has been in storage for 26.5 years contains 14.5g of C
Zarrin [17]

Answer:

464 grams.

Step-by-step explanation:

Amount of substance:

The amount of substance after t years is given by an equation in the following format:

A(t) = A(0)(1-r)^t

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Co-60 has a half life of 5.3 years.

This means that:

A(5.3) = 0.5A(0)

We use this to find r. So

A(t) = A(0)(1-r)^t

0.5A(0) = A(0)(1-r)^{5.3}

(1-r)^{5.3} = 0.5

\sqrt[5.3]{(1-r)^{5.3}} = \sqrt[5.3]{0.5}

1 - r = 0.5^{\frac{1}{5.3}}

1 - r = 0.8774

So

A(t) = A(0)(0.8774)^{t}

If a pellet that has been in storage for 26.5 years contains 14.5g of Co-60, how much of this radioisotope was present when the pellet was put in storage?

We have that A(26.5) = 14.5, and use this to find A(0). So

A(t) = A(0)(0.8774)^{t}

14.5 = A(0)(0.8774)^{26.5}

A(0) = \frac{14.5}{(0.8774)^{26.5}}

[tex]A(0) = 464[tex]

464 grams.

3 0
3 years ago
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