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4 years ago

14

Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the w

estern station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?
i got 646

2 answers:

Dovator [93]4 years ago

8 0

I think you might be right.

Alisiya [41]4 years ago

7 0

Answer:

I believe you are correct

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Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin

sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

$\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}$

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x$

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3 years ago

Please help!!!!<br> Thank you!

Rudik [331]

Answer:

option 3, 900 square units

Step-by-step explanation:

area=20*(32+13)

=900

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3 years ago

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Step-by-step explanation:

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3 years ago

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ser-zykov [4K]

Answer:

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3 years ago

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Taya2010 [7]

12 1/4 - 3 3/5 =
49/4 - 18/5 =
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3 years ago