What is the total surface area of the square pyramid below?

Bryan created a scale drawing of his rectangular bedroom. His drawing had dimensions of 6 inches by 8 inches. If the scale that

vlabodo [156]

Answer:

56 feet

Step-by-step explanation:

If 1 inch = 2 feet, we can first find the actual dimensions of his room by multiplying the number of inches by 2.

6(2)

= 12

8(2)

= 16

So, the actual dimensions of his room are 12 feet by 16 feet.

To find the perimeter, use the perimeter formula, P = 2l + 2w.

Plug in the length and width:

P = 2l + 2w

P = 2(12) + 2(16)

P = 24 + 32

P = 56

So, the perimeter of his actual room is 56 feet.

6 0

2 years ago

Simplify to the extent possible:<br><br> (logx16)(log2 x)

olga55 [171]

Answer:

Step-by-step explanation:

Use the change-of-base rule.

4 0

2 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

Which linear equation represents the data given in the table?

bekas [8.4K]

The answer is C y=6x-6

6 0

3 years ago

Using the following image, solve the problems below given that U is the midpoint point of TV.

Inessa05 [86]

Answer:

see explanation

Step-by-step explanation:

Given that U is the midpoint of TV, then

TU = UV , substitute values

8x + 11 = 12x - 1 ( subtract 12x from both sides )

- 4x + 11 = - 1 ( subtract 11 from both sides )

- 4x = - 12 ( divide both sides by - 4 )

x = 3

Thus

TU = 8(3) + 11 = 24 + 11 = 35

UV = 12(3) - 1 = 36 - 1 = 35

8 0

3 years ago