Step-by-step explanation:
In the attached images we can see the rigid transformation of the function 
1. The basic graph
2. The reflected graph 
3. The displaced graph 
Reflection: In the expression , the sign - before the parenthesis indicates that the function is reflected in the x axis, for this case the function is even, this means that -f(x) = f(-x)
, then the reflection on the x axis is equal to the reflection on the y axis.
Displacement: We observe the term (x-4) of the function and analyze the value -4, where, the sign - indicates displacement to the right and the value 4 indicates the amount that the graph shifted
.
You can write a system of equations, I'm pretty sure.
the first equation would be
10a+3f+.5c=100
and
a+f+c=100
For the first equation, its the price of each ticket that adds up to 100 tickets
For the second equation, its the amount of people that adds up to 100 people.
I'm pretty sure this is the route to go but I haven't solved it for myself (yet) I'll probably comment the answer if you need me to
Answer:
the center- like- of a bowel- is the middle- bru.h im trying to be mean but ;-;
Step-by-step explanation:
Answer:
They took 4,180 minutes total to complete the course.
Step-by-step explanation:
The average time is given by the sum of each individual time of the members divided by the number of members on the group. So if we want to know the total time they took to complete the course we need to take the average and multiply it by the number of people in the group. So we have:
total time = average*number of members = 110*38 = 4180 minutes
They took 4,180 minutes total to complete the course.
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
