The equation of the line is:
y-yo = m (x-xo)
Where,
m = (y2-y1) / (x2-x1)
Substituting values:
m = (8-4) / (6-2)
m = (4) / (4)
m = 1
Then, the equation is:
y-4 = 1 * (x-2)
Rewriting:
y = x-2 + 4
y = x + 2
The midpoint is:
k = ((x1 + x2) / 2, (y1 + y2) / 2)
k = ((2 + 6) / 2, (4 + 8) / 2)
k = ((8) / 2, (12) / 2)
k = (4, 6)
Then, the equation of the perpendicular line that passes through k is:
y = -x + b
Looking for b we have:
6 = -4 + b
b = 6 + 4
b = 10
Substituting:
y = -x + 10
Answer:
An equation of a line perpendicular to jl and passing through k is:
y = -x + 10
This will help a lot if you go to desmos! Just graph the equation on there! It’s much easier to see on computer
X=14
Y=15
Im assuming you want to find out what x and y are
Step-by-step explanation:
(qvp)5=4-5=54643434346
3x +2= 5x
-3x
2= 2x
/2
1= x
So first I got all the x’s on one side and the whole numbers on the other side. So we had 2 on one side and 2x on the other. From there we divided by the number of x’s which was 2 so we can get one x only. So 2/2= 1 so x =1
