Answer:
4cotα=tanα
4(1/tanα)=tanα
(4/tanα)=tanα
cross multiply
=> 4=tan²α
√4=√tan²α
±2=tanα
α=arc( tan) |2|
α=63.4° ( in first quadrant)
and
α=180+63.4=243.4 in the third quadrant
since we also found a negative answer( i.e –2) then α also lies in quadrants where it gives a negative value(i.e second and fourth quadrants)
α=180–63.4=116.6° in the second quadrant
α=360–63.4=296.6 in the fourth quadrant
therefore theta( in my case, alpha) lies in all four quadrants and is equal to:
α=63.4°,243.4°,116.6°and 296.6°
The refrection of a point or set of points across the line y = x will result in a point or set of points whose coordinates are the interchange of the x-value and the y-value of the original point or set of points.
Given that the vertices of a triangle are P(-8, 6), Q(1, -3) and R(-6, -3), the vertices of the triangle formed by the refrection Ry=x<span>(ΔPQR) are P'(6, -8), Q'(-3, 1) and R'(-3, -6).</span>
Answer:
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.
Step-by-step explanation:
let S be the sample space for the inspection of the light bulbs.
Therefore, n(s) = 800
let ' A ' be the event of no defects bulbs.
Therefore, n(A) = 796
Now the Experiment probability for a light bulb chosen has no defects will be given by,
Substituting the values we get
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.
I have no idea how to answer this maybe post the repeal
Answer:
(x+2)(x+7)(x+i)(x-i)
Step-by-step explanation:
I just took the quiz.
