We are trying to represent the change in position of a bird flying down 7 ft to the ground.
Often, for the y axis- up is positive and down is negative.
Change in position is displacement- how far it was from the starting point
( different from distance which is how far is traveled
ex. doubling back would have distance they traveled some distance while the displacement is 0 because they are back to where they started).
The bird is going down 7 ft from where it originally was, which can be represented by
Bird's displacement = -7 ft
Answer:
The correct option is D) 
Step-by-step explanation:
Consider the provided information.
People are entering a building at a rate modeled by f (t) people per hour and exiting the building at a rate modeled by g (t) people per hour,
The change of number of people in building is:

Where f(t) is people entering in building and g(t) is exiting from the building.
It is given that "The functions f and g are non negative and differentiable for all times t."
We need to find the the rate of change of the number of people in the building.
Differentiate the above function with respect to time:
![h'(x)=\frac{d}{dt}[f(t)-g(t)]](https://tex.z-dn.net/?f=h%27%28x%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Bf%28t%29-g%28t%29%5D)

It is given that the rate of change of the number of people in the building is increasing at time t.
That means 
Therefore, 
Hence, the correct option is D) 
Answer:
1/2, 0.55, 5/7 is your answer
Step-by-step explanation:
Change each into decimal
1/2 = 0.50
0.55 = 0.55
5/7 = ~0.71
0.50 < 0.55 < 0.71
~
Henson's cost: 3x+y=203
Garcia's cost: 2x+3y=189
Step-by-step explanation:
Given,
Cost of each adult ticket = x dollars
Cost of 3 adult ticket = 3x
Cost of 2 adult ticket = 2x
Cost of each child ticket = y dollar
Cost of 3 child ticket = 3x
Henson's cost;
3 adult tickets + 1 child ticket = $203
3x+y=203
Garcia's cost;
2 adult tickets + 3 child tickets = $189
2x+3y=189
Henson's cost: 3x+y=203
Garcia's cost: 2x+3y=189
Keywords: linear equation, addition
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