All categories

3 years ago

Help me please!! Slope

Mathematics

1 answer:

Nat2105 [25]3 years ago

4 0

1. Y=3/1+b
2. Y=-1/2+b
3. Y=-3/3+b
4. I can’t quiet remember how to do sorry :/

You might be interested in

If m∠2 = 41°, m∠5 = 94°, and m∠10 = 109°, find each measure.

Orlov [11]

Answer:

Step-by-step explanation:

It's given in this question,

m∠2 = 41°, m∠5 = 94° and m∠10 = 109°

Since, ∠2 ≅ ∠9 [Alternate interior angles]

m∠2 = m∠9 = 41°

m∠8 + m∠9 + m∠10 = 180° [Sum of angles at a point of a line]

m∠8 + 41 + 109 = 180

m∠8 = 180 - 150

m∠8 = 30°

Since, m∠2 + m∠7 + m∠8 = 180° [Sum of interior angles of a triangle]

41 + m∠7 + 30 = 180

m∠7 = 180 - 71

m∠7 = 109°

m∠6 + m∠7 = 180° [linear pair of angles]

m∠6 + 109 = 180

m∠6 = 180 - 109

= 71°

Since m∠5 + m∠4 = 180° [linear pair of angles]

m∠4 + 94 = 180

m∠4 = 180 - 94

m∠4 = 86°

Since, m∠4 + m∠3 + m∠9 = 180° [Sum of interior angles of a triangle]

86 + m∠3 + 41 = 180

m∠3 = 180 - 127

m∠3 = 53°

m∠1 + m∠2 + m∠3 = 180° [Angles on a point of a line]

m∠1 + 41 + 53 = 180

m∠1 = 180 - 94

m∠1 = 86°

8 0

3 years ago

What’s 1 fourth of 1490

Kazeer [188]

1490/4 =372.5................

4 0

2 years ago

Read 2 more answers

What are the coordinates of the point on the directed line segment from (-6, -6)(−6,−6) to (9, -1)(9,−1) that partitions the seg

GrogVix [38]

Answer:

(0, -4)

Step-by-step explanation:

The coordinates of the points from which the directed line segment extends = (-6, -6) to (9, -1)

The ratio the required point partitions the line = 2 to 3

The formula for finding the coordinate of a point that partitions a line AB into a ratio 'a' to 'b', where the coordinates of, A = (x₁, y₁) and B = (x₂, y₂) is given as follows;

$\left(\dfrac{a}{a + b} \times (x_1 - x_2)+ x_1, \ \dfrac{a}{a + b} \times (y_1 - y_2)+ y_1 \right)$

Therefore, the required point is located as follows;

$\left(\dfrac{2}{2 + 3} \times (9 - (-6))+ (-6), \ \dfrac{2}{2 + 3}\times (-1 - (-6))+ (-6) \right) = (0, -4)$

The coordinates of the point is (0, -4)

6 0

3 years ago

How would you solve this problem.

Jet001 [13]

We can find h by calculating the area S of the parallelogram in two ways. We can write: $S=18\cdot10$ . On the other hand, $S=12\cdot h$ . Then:

$18\cdot10=12\cdot h\\\\ 12h=180\\\\h=\dfrac{180}{12}\\\\\boxed{h=15}$

7 0

2 years ago

TRIGONOMETRY , can you solve this plz:(<br>even if you know one of them,plz help:)

daser333 [38]

Answer:

See below

Step-by-step explanation:

$\frac{1}{1-cos A} - \frac{1}{1+cos A} =2 cosec A cot A \\ \\ L. H. S.= \frac{1}{1-cos A} - \frac{1}{1+cos A} \\ \\ = \frac{1+cos A - (1 - cos A)}{(1-cos A)(1+cos A)}\\ \\ = \frac{1+cos A - 1 + cos A}{1-cos^{2} A}\\ \\ = \frac{2cos A }{sin^{2} A}\\ \\ =2 .\frac{1}{sin A}.\frac{cos A }{sin A}.\\ \\ = 2.cosec \: A.cot \: A \\ \\ = R.H.S$

5 0

2 years ago