Answer:
the median is 43
Step-by-step explanation:
Answer:
1250 m²
Step-by-step explanation:
Let x and y denote the sides of the rectangular research plot.
Thus, area is;
A = xy
Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.
Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;
2x + y = 100
Thus, y = 100 - 2x
Since A = xy
We have; A = x(100 - 2x)
A = 100x - 2x²
At maximum area, dA/dx = 0.thus;
dA/dx = 100 - 4x
-4x + 100 = 0
4x = 100
x = 100/4
x = 25
Let's confirm if it is maximum from d²A/dx²
d²A/dx² = -4. This is less than 0 and thus it's maximum.
Let's plug in 25 for x in the area equation;
A_max = 25(100 - 2(25))
A_max = 1250 m²
X2 + 12 = 7x x2 – 7x + 12 = 0factor the equation (x – 3 ) ( x – 4 ) = 0 Then equating both factor to 0 X – 3 = 0 X = 3 And X – 4 = 0 X = 4 So the answer is X = 3 X =4
Answer:
8.0, 16.0
Step-by-step explanation:
times the before number by itself
