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N76 [4]
3 years ago
9

In an optical fibre, the power drops by a factor of 10 approximately every 30 km. If the transmit power is 0. 35 W, how far will

a signal be transmitted before the power is attenuated to 350 μW?
Mathematics
1 answer:
IgorC [24]3 years ago
4 0

Answer:

  • 30000 km

Step-by-step explanation:

First convert the transmit power into μW, considering 1 W = 1000000 μW:

  • 0.35 W = 0.35*1000000 μW = 350000 μW

Find how many factors of 10 the power dropped:

  • 350000 / 350 = 1000

Find the distance:

  • 1000*30 km = 30000 km
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Answer: Using the proportion beteween the sides of the similar triangles, the distance between the endpoints of the beams P and Q is 3.2 inches.

Option a. 3.2 inches


Solution

PR=3.7 inches; CR=5.6 inches; AC=4.9 inches

As the two triangles QRP and ARC are similar, their sides must be proportionals, then:

PQ/AC=PR/CR=QR/AR

Replacing the given values in the proportion above:

PQ/(4.9 inches)=(3.7 inches)/(5.6 inches)=QR/AR

PQ/(4.9 inches)=3.7/5.6

Solving for PQ: Multiplying both sides of the equation by 4.9 inches:

(4.9 inches)[PQ/(4.9 inches)]=(4.9 inches)(3.7/5.6)

PQ=(4.9)(3.7)/5.6 inches

PQ=18.13/5.6 inches

PQ=3.2375 inches

Rounding to one decimal place:

PQ=3.2 inches


5 0
3 years ago
Read 2 more answers
Plz help I don't get it
RSB [31]
31. Answer: 6 over 9
32. Answer: 12 over 20
34. Answer: 15 over 18
35. Answer: 24 over 32
Hope this was found helpful to you!
I was my pleasure assisting you!
7 0
4 years ago
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sukhopar [10]

Answer:

  • dilation: angle measure
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Step-by-step explanation:

The "rigid" transformations, reflection, rotation, translation, preserve both angle and length measures.

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3 years ago
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