Triangle XYZ was dilated by a scale factor of 2 to create triangle ACB and cos ∠X = 2 and 5 tenths over 5 and 59 hundredths.

Mathematics

1 answer:

Paha777 [63]3 years ago

6 0

Answer:

cosx=2.5/5.59

" =.4472.......

"x" =63.434°; so "a" is=.

When talking about triangles and a scale; the angles remain=. In this case; "a" and "x"; y=c; z=b.

The sides are 2x or x/2.

There's not enough imfo to give you measurements. You need at least: asa, sas or sss.

One formula is: a/sinα=b/sinβ=c/sinγ.

Step-by-step explanation:

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Find the length of the function over the given interval. y = 3x from x = 0 to x = 2

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The length of the function y = 3x over the given interval [0, 2] is 3.2 units

For given question,

We have been given a function y = 3x

We need to find the length of the function on the interval x = 0 to x = 2.

Let f(x) = 3x where f(x) = y

We have f'(x) = 3, so [f'(x)]² = 9.

Then the arc length is given by,