Below = a negative number (-)
-2
up = positive number
5
the equation would be -2+5 = ?
and the answer/ integer that represents the new location is 3
Answer:
x = StartFraction negative 2 plus or minus StartRoot 2 squared minus 4(4)(negative 1) EndRoot Over 2(4) EndFraction
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
![ax^2+bx+c=0](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0)
is equal to
![x=\frac{-b(+/-)\sqrt{b^2-4ac} }{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%28%2B%2F-%29%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D)
in this problem we have
![4x^2 + 2x - 1=0](https://tex.z-dn.net/?f=4x%5E2%20%2B%202x%20-%201%3D0)
so
![a=4](https://tex.z-dn.net/?f=a%3D4)
![b=2](https://tex.z-dn.net/?f=b%3D2)
![c=-1](https://tex.z-dn.net/?f=c%3D-1)
substitute in the formula
![x=\frac{-2(+/-)\sqrt{2^2-4(4)(-1)} }{2(4)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-2%28%2B%2F-%29%5Csqrt%7B2%5E2-4%284%29%28-1%29%7D%20%7D%7B2%284%29%7D)
therefore
x = StartFraction negative 2 plus or minus StartRoot 2 squared minus 4(4)(negative 1) EndRoot Over 2(4) EndFraction
There aren't any answer options so I will just simplify the expression:
10(2p+q)
20p+10q
The perimeter of the shape is 30 add all the sides