Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
Answer:
A. (6,0)
Step-by-step explanation:
4a- 5b = 24
Check each point to see if its is true
A. (6,0)
4(6) - 5(0) = 24
24 = 24
true
B. (-5, -2)
4(-5) -5(-2)= 24
-20 +10 = 24
-10 =24
False
C. (0,6)
4(0) -5(6) =24
-30 =24
False
D. (-2, -5)
4(-2) -5(-5)=24
-8+25=24
18=24
False
Answer:
Step-by-step explanation:
We are given the following recursive formula:
And consider 
a2
a3
a4
Answer:
...
Step-by-step explanation:
Answer:
Step-by-step explanation:
Three times a number x : 3x
Three times a number x increase by 4: 3x +4
Five times the number x: 5x
5x = 3x +4
Subtract 3x from both the sides.
5x - 3x = 3x +4 - 3x
2x = 4
Divide both sides by 2
2x/2 = 4/2
x=2
The number is 2
