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Serggg [28]
3 years ago
7

choose an equation in slope-intercept form for the line that passes through (-8,1) and is perpendicular to the y=2x-17. select o

ne: a. y= -(1/2)x - 5 b. y= -2x - 4 c. y= -(1/2)x - 3 d. y= -2x 1
Mathematics
1 answer:
Fed [463]3 years ago
5 0
Y = 2x - 17, comparing to y = mx + c, slope m = 2.

If perpendicular, the new slope would be -1/2, that is the negative reciprocal of 2.

And passing through (-8 , 1).

using y = mx + c,  and x = -8,  y = 1,  m = -1/2

1 = -1/2*-8 + c

1 = 4 + c

1 - 4 = c

c =  -3

y = mx + c,  substituting m = -1/2, and c = -3,    y = -(1/2)x - 3.

Option C.
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A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?
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Answer:

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Step-by-step explanation:

You have the function f(x) given by:

f(x)=\frac{1}{2^{2x}}   (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]  (2)

To solve this derivative you use the following derivative formula:

\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

-2(ln2)2^{-2x}=-1

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235

With this value you calculate f(a):

f(a)=\frac{1}{2^{2(0.235)}}=0.721

Next, you use the general equation of line:

y-y_o=m(x-x_o)

for xo = a = 0.235 and yo = f(a) = 0.721:

y-0.721=(-1)(x-0.235)\\\\y=-x+0.956

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

0=-x+0.956\\\\x=0.956

hence, the x-intercept of the tangent line is 0.956

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