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It would be called a Hexagon.
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Answer:
139558.6
Step-by-step explanation:
Answer:
100
Step-by-step explanation:
i think
Use the substitution method:
2x - 6y = -12
x - 2y = -8
Then x = 2y - 8
Substitute in the first equation:
2(2y - 8) - 6y = -12
4y - 16 - 6y = -12
-2y = 4
y = -2
Now substitute y in one of the two equations given you prefer:
For example x-2*(-2) = -8
x + 4 = -8
x = -12
The solutions are x = -12 and y = -2
Answer:
The answer is (7, 8) and (0,−6).
Step-by-step explanation:
The given system has two equations, one is the linear and the other is non-linear.
Let,
y = x^2 - 5x - 6 equation 1
y = 2x - 6 equation 2
Step 1: Equating both equations for the value of x
x^2 - 5x - 6 = 2x -6
x^2 -5x +5x - 6 = 2x + 5x - 6
x^2 -6 +6 = 7x -6 +6
x^2 - 7x = 7x - 7x
x^2 -7x = 0
x ( x - 7) = 0
implies that,
x = 0 OR x - 7 = 0 ⇒ x = 7
Now pick any of the two equations of y to find the solution. I'll choose the equation 2.
the value of y, for x = 0
y = 2(0) - 6
y = - 6
the value of y, for x = 7
y = 2(7) -6
y = 14 - 6
y = 8
hence, (0,-6) and (7, 8) are the solutions to the given system of equations.
