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Scrat [10]
2 years ago
15

Imagine using two of these triangles to construct a figure. What are the characteristics of the figure? Select all that apply. I

t’s a rectangle. Opposite sides are congruent. All sides are congruent. Opposite sides are parallel. All angles are right angles.
Mathematics
2 answers:
Arte-miy333 [17]2 years ago
7 0

Answer:

The correct answer is A,B,D,E

Step-by-step explanation:

i did the work on edg and got it right

Rasek [7]2 years ago
4 0

Answer:

A, B, D, E :)

Step-by-step explanation:

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Help please! Need answer!! Not test!!!
Ann [662]

There are two ways to list the angles:

1) Simply name them based on the points:

∠W , ∠X , ∠Y , ∠Z

2) The way that I believe that you are supposed to list them in this case. List them as such:

∠WYZ , ∠YZX , ∠ZXW , ∠XWY

~

6 0
3 years ago
What is the product of the sum of eight and two and the difference between eight and two? Show all work.
meriva
<h2>Answer:</h2><h3>=60</h3><h2>Step-by-step explanation:</h2><h3>=Solution:</h3><h3> (8+2) × (8-2)</h3><h3> =10×6</h3><h3> =60#</h3>
3 0
2 years ago
Write equivalent expression for 7× + 4× + 3-1
Mazyrski [523]

Answer: you just flip it. It would be the opposite.

Step-by-step explanation:

When you flip it, what’s the difference? It’s still the same.

6 0
3 years ago
Emil is itemizing deductions on his federal income tax return and had $1900 in non-reimbursed work expenses last year. If his AG
a_sh-v [17]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below are the choices that can be found from other source:

A.$340 
<span>B.$1560 </span>
<span>C.$38 </span>
<span>D.$1862</span>

Below is the solution:

78000 x .0.02=1560 
<span>1900 - 1560=340</span>
5 0
3 years ago
Read 2 more answers
In a class of 40 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose
ladessa [460]

Answer:3

Step-by-step explanation:

Given

There are total 40 students in a class

No of students with Pierced Nose n(N)=7

No of students with Pierced ear n(E)=36

and we know using sets

n\left ( N\cup E\right )=n\left ( E\right )+n\left ( N\right )-n\left ( N\cap E\right )

where n\left ( N\cup E\right )=Students either nose or ear Pierced

n\left ( N\cap E\right )=no of students having both nose and ear pierced

40=7+36-n\left ( N\cap E\right )

n\left ( N\cap E\right )=43-40=3

3 0
3 years ago
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