Y = 8^x
For (0, 1): 1 ≠ 8^0 = 1
For (8, 1): 1 ≠ 8^8 = 16,777,216
For (2, 64): 64 = 8^2
For (0, 8): 8 ≠ 8^0 = 1
Therefore, option 3, (2, 64) is the correct answer.
Answer:
Every number of years 365 and I have been trying to get a hold of
#1. B
<span>(z * z^2 + z * 2z + z * 4) – (-2 *z^2 – (-2) 2z – (-2) 4)
Z^3 + 2z^2 + 4z – 2z^2 -4z – 8
Z^3 + 2z^2 – 2z^2 + 4z – 4z – 8
Z^3 - 8
</span>
#2 and #3. D
<span>(x + y)(x + 2)
x^2 + 2x + yx + 2y
</span>
#4. D.
<span>(x - 7)(x + 7)(x- 2)
x^2 + 7x – 7x -49
x^2 + x – 49
x^2 -49
(x^2 – 49 ) (x – 2)
x^3 – 2x^2 – 49x + 98
</span>
#5. C
(y - 4) = 0
y = 4
(x + 3)= 0
x = -3
#6. A and B
Answer:
Yes you are correct.
Step-by-step explanation:
Answer:
−7
Step-by-step explanation:
