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const2013 [10]
3 years ago
9

146 Mathe Functional skills Level 1 Diagnostic

Mathematics
2 answers:
geniusboy [140]3 years ago
6 0

Answer:

31

Step-by-step explanation:

56-25=31

natita [175]3 years ago
3 0

Answer:

31

Step-by-step explanation:

56-25=31 (the range is the difference between the smallest and the biggest number)

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The ages in years of 10 teachers of a school are : 32, 41, 28, 54, 35, 26, 23, 33, 38, 40. What is the range of ages of the teac
PSYCHO15rus [73]

Answer:

The range is 31

Step-by-step explanation:

Range is highest number - lowest number.

The highest number is 54 and the lowest is 23.

54-23=31

4 0
3 years ago
Tell me the answer of these question.
Nonamiya [84]
16. \ \ V= \pi r^2h \ \to \ r^2= \cfrac{V}{ \pi h}  \ \to \ \boxed{r= \sqrt{ \frac{V}{ \pi h} } } \\ \\ \\ 17.\ \ d= \frac{1}{2} at^2 \ \to \ 2d= at^2   \ \to \ t^2= \cfrac{2d}{a} \   \to \ \boxed{t= \sqrt{\frac{2d}{a}}} \\  \\   \\ 18. \ \ S=180(n-2) \ \to \  \cfrac{S}{180}=n-2 \ \to \ \boxed{n= \frac{S}{180}+2 }
6 0
3 years ago
Help me please‼️
aksik [14]

Answer:

a.

500x+0.04=y

400x+0.05=y

for percentages move decimal to the left twice

4 0
3 years ago
Which of the following is equivalent to tan2θcos(2θ) for all values of θ for which tan2θcos(2θ) is defined?
Aloiza [94]

Answer:

2sin²θ - tan²θ

Step-by-step explanation:

Given

tan²θcos(2θ)

Required

Simplify

We start by simplifying cos(2θ)

cos(2θ) = cos(θ+θ)

From Cosine formula

cos(A+A) = cosAcosA - sinAsinA

cos(A+A) = cos²A - sin²A

By comparison

cos(2θ) = cos(θ+θ)

cos(2θ) = cos²θ - sin²θ ----- equation 1

Recall that cos²θ + sin²θ = 1

Make sin²θ the subject of formula

sin²θ = 1 - cos²θ

Substitute sin²θ = 1 - cos²θ in equation 1

cos(2θ) = cos²θ - (1 - cos²θ)

cos(2θ) = cos²θ - 1 +cos²θ

cos(2θ) = cos²θ + cos²θ - 1

cos(2θ) = 2cos²θ - 1

Substitute 2cos²θ - 1 for cos(2θ) in the given question

tan²θcos(2θ) becomes

tan²θ(2cos²θ - 1)

Open brackets

2cos²θtan²θ - tan²θ

------------------------

Simplify tan²θ

tan²θ = (tanθ)²

Recall that tanθ =  sinθ/cosθ

So, we have

tan²θ = (sinθ/cosθ)²

tan²θ = sin²θ/cos²θ

------------------------

Substitute sin²θ/cos²θ for tan²θ

2cos²θtan²θ - tan²θ becomes

2cos²θ(sin²θ/cos²θ) - tan²θ

Open bracket (cos²θ will cancel out cos²θ) to give

2(sin²θ) - tan²θ

2sin²θ - tan²θ

Hence, the simplification of tan²θcos(2θ) is 2sin²θ - tan²θ

Option E is correct

7 0
2 years ago
Is this a function pls help me
Olin [163]

Answer:

no

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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