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ch4aika [34]
3 years ago
11

A vertical pole 32 feet tall stands on a hillside that makes an angle of 17° with the horizontal line. Determine the approximate

length of cable that would be needed to reach
from the top of the pole to a point 56 feet downhill from the base of the pole. Round answer to two decimal places.
A. 72.17 feet
D. 68.24 feet
B. 76.77 feet
E. 55.79 feet
C. 63.98 feet
Help ASAP It’s a test
Mathematics
2 answers:
blagie [28]3 years ago
6 0
The answer would be A
kompoz [17]3 years ago
5 0

Answer:

The 72 feet is measured on the slope, not out from the pole horizontally. I get

top of pole is at

40 + 72 sin17°

downhill point is

72 cos 17°

from point beneath the pole

cable^2 = (40+72 sin17°)^2 + (72 cos 17°)^2

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Setler [38]
<h2>Answer: </h2>

1. <u>Area = b × h</u>

A = 5 × 3

A = 15cm².

2. <u>Area = ½(a + b) × h</u>

A = ½(9 + 15) × 15

A = ½ × 24 × 15

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A = 180mm².

3. <u>Area = 2(l × b) + l × b</u>

A = 2(12 × 4) + 6 × 3

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A = 114m².

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padilas [110]

Step-by-step explanation:

<u>Formula:</u>

\boxed{a = 3.14(r)^{2} }

r represents the radius.

The radius is 1/2 of the diameter.

Since 1/2 of 16 is 8, 8 is our radius.

<u>Substitute:</u>

a = 3.14(8)^{2}

<u>Solve:</u>

a = 3.14(64)

a = 200.96in^{2}

6 0
2 years ago
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Svetach [21]

Answer:

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