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love history [14]
4 years ago
6

Given the data set (4, 85), (7, 92), (14, 110), which of the following equations best represents a line of best fit?

Mathematics
2 answers:
nataly862011 [7]4 years ago
7 0
Let's see if there is a constant rate first...

(92-85)/(7-4)=7/3

(110-92)/(14-7)=18/7  so there is no constant rate...so the line of best fit (linear least squares regression line) will have a slope of:

m=(nΣxy-ΣxΣy)/(nΣx^2-ΣxΣx)

m=(3*2524-25*287)/(3*261-625)

m=397/158

b=(Σy-mΣx)/n

b=(158Σy-397Σx)/(3*158)

b=(45346-9925)/(3*158)

b=11807/158

So the line of best fit is:

y=(397x+11807)/158

so approximating this line....

y≈2.5x+74.73

So the closest that you have is:

y=7x/3+75.67
Readme [11.4K]4 years ago
5 0
Answer A should be the correct answer
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Please help this for my pre calculus finals
dsp73

Answer:

a) It will take 17.71 years

b) It will take 17.58 years

c) I will earn $6.60 more in compound continuously

Step-by-step explanation:

a) Lets talk about the compound interest

- The formula for compound interest is A = P (1 + r/n)^(nt)

, Where:

- A = the future value of the investment, including interest

- P = the principal investment amount (the initial deposit)

- r = the annual interest rate (decimal)

- n = the number of times that interest is compounded per unit t

- t = the time the money is invested

* Lets solve the problem

∵ The money deposit is $2000

∵ The rate is 6.25%

∵ The interest is compound quarterly

∵ The future value is $6000

∴ P = 2000

∴ A = 6000

∴ r = 6.25/100 = 0.0625

∴ n = 4

∴ t = ?

∵ A = P (1 + r/n)^(nt)

∴ 6000 = 2000 (1 + 0.0625/4)^4t ⇒ divide both sides by 2000

∴ 3 = (1.015625)^4t ⇒ insert ㏑ for both sides

∴ ㏑(3) = ㏑(1.015625)^4t

∵ ㏑(a)^b = b ㏑(a)

∴ ㏑(3) = 4t ㏑(1.015625) ⇒ divide both sides by ㏑(1.015625)

∴ 4t = ㏑(3)/㏑(1.015625) ⇒ divide both sides by 4

∴ t = [㏑(3)/㏑(1.015625)] ÷ 4 = 17.71

* It will take 17.71 years

b) Lets talk about the compound continuous interest  

- Compound continuous interest can be calculated using the formula:

  A = P e^rt  

- A = the future value of the investment, including interest

- P = the principal investment amount (the initial amount)

- r = the interest rate  

- t = the time the money is invested

* Lets solve the problem

∵ The money deposit is $2000

∵ The rate is 6.25%

∵ The interest is compound continuously

∵ The future value is $6000

∴ P = 2000

∴ A = 6000

∴ r = 6.25/100 = 0.0625

∴ t = ?

∵ A = P e^rt  

∴ 6000 = 2000 e^(0.0625 t) ⇒ divide both sides by 2000

∴ 3 = e^(0.0625 t) ⇒ insert ㏑ to both sides

∴ ㏑(3) = ㏑[e^0.0625 t]

∵ ㏑(e^a) = a ㏑(e) ⇒ ㏑(e) = 1 , then ㏑(e^a) = a

∴ ㏑(3) = 0.0625 t ⇒ divide both sides by 0.0625

∴ t = ㏑(3)/0.0625 = 17.5778

* It will take 17.58 years

c) If t = 5 years

# The compound quarterly:

∵ A = P (1 + r/n)^(nt)

∴ A = 2000 (1 + 0.0625/4)^(4×5)

∴ A = 2000 (1.015625)^20 = $2727.08

# Compound continuously

∵ A = P e^(rt)

∴ A = 2000 e^(0.0625×5) = $2733.68

∴ I will earn = 2733.68 - 2727.08 = $6.60

* I will earn $6.60 more in compound continuously

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Answer:

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Answer:

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Step-by-step explanation:

We are given the following in the question:

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V=Bh

where B is the area of base and h is the height of cylinder.

Volume of cylinder =

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Base area =

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We have to find height of cylinder.

h = \dfrac{V}{B}\\\\h = \dfrac{6\pi x^7-6\pi x^4-20\pi x^2}{2\pi x^2}\\\\h = 3x^5-3x^2-10\text{ units}

Thus, the height of cylinder is 3x^5-3x^2-10 units.

6 0
3 years ago
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