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Radda [10]
3 years ago
9

PLEASE HELP !! ILL GIVE BRAINLIEST !!

Mathematics
2 answers:
9966 [12]3 years ago
4 0

Answer:

<PQN and MNQ

Step-by-step explanation:

hope this helps...

MrMuchimi3 years ago
3 0

Answer:

pqs and onl

Step-by-step explanation:

pqs onl

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Help, will give brainlist!!
Licemer1 [7]

Answer:

<u>Fred.</u>

Started hang gliding at a height of 700 ft and descends 15 feet every seconds

<u>Gene</u>

Started hang gliding at a height of 575 ft and descends 10 feet every seconds

Step-by-step explanation:

The function that models Fred's hang gliding is f(x)=-15x+700

The initial value is 700 feet. This Fred was 700 feet above see level before he starts descending.

The rate of descent is -15 ft/s. This means Fred descends 15 feet in one second.

From the table the initial height is 575 ft. This means Gene was 575 feet above sea-level at the beginning of the hang gliding.

The rate of descent is \frac{565-575}{1-0} =-10 ft/s.

This means that in every seconds, Gene descends 10 feet.

4 0
3 years ago
Help with this and you will get brainly
vlada-n [284]

Answer:

The two that are blank are 2 and 7

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Help pls will give 10 points​
patriot [66]

Answer:

In the picture

Step-by-step explanation:

I hope that it's a clear explanation.

4 0
3 years ago
It is desired to draw blood 3 cm up a capillary tube. Assuming a contact angle of 0 degrees and a blood density of 1060 kg/m3, w
JulijaS [17]

Answer:

If we assume a temperature of 20ºc and the blood interfacial surface tension is similar to water interfacial surface tension, the diameter of the capillary tube should be 0.933mm.

Step-by-step explanation:

The Jurin law describes the height a fluid can reach in a capillary tube. This law can be written as:

H=\displaystyle\frac{2\gamma cos(\theta)}{\rho gr}

where γ is the interfacial surface tension, θ is the contact angle with the fluid, ρ is the fluid density, g is the gravity acceleration and r is the tube radius.

If we assume that the interfacial surface tension of blood and water are almost the same, γ=0,0728 N/m at 20ºc. Therefore the diameter of the tube will be:

D=2r=\displaystyle\frac{4\gamma cos(\theta)}{\rho gH}=0.933\cdot 10^{-3}m

4 0
3 years ago
Arrange the numbers in order from greatest to least.Please and don’t come on her if you don’t know the answer because that’s jus
EastWind [94]

Answer:

4π, √150, 11 4/9 hope it helps

Step-by-step explanation:

I am so sorry if I am wrong

6 0
3 years ago
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