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Art [367]
3 years ago
5

Solve the following equation for x: 2(5x+6)+3x=38

Mathematics
1 answer:
gregori [183]3 years ago
4 0

Answer:

x=2

Hope this helps! Have a good day! :)

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The new club sticker is in the shape of a triangle. It has a height of 8 inches and a base of 10 inches. The area of the club st
rusak2 [61]

Answer:

40 square inches.

Step-by-step explanation:

It is given that the new club sticker is in the shape of a triangle.

Height of triangle = 8 inches

Base of triangle = 10 inches

We need to find the area of sticker.

Area of triangle =\dfrac{1}{2}\times base \times height

Substitute base = 10 and height = 8 in the above formula.

Area of triangle =\dfrac{1}{2}\times 10\times 8

Area of triangle =\dfrac{80}{2}

Area of triangle =40

Therefore, the area of the club sticker is 40 square inches.

5 0
4 years ago
Verify<br>a x (b+c) = a x b + a x c for a =<br>-1/6 b=4/7 c=-2/5​
SVETLANKA909090 [29]

Step-by-step explanation:

✓(-1/6×4/7)+(-1/6×-2/5)

✓(-4/42)+(2/30)

✓(-2/21)+(1/15)

✓(-2/21+1/15)

=-<u>1/35</u>

3 0
3 years ago
Can someone complete the square
pshichka [43]
To do these, start by looking at the "b" value -6.
divide it by 2

-6/2 = -3

now square this number

(-3)^2 = 9

this is what you need for the "c" value

there is only a 5 for the c value so add 4 to both sides of the equation. ( +4 = +4)

y +4 = x^2 -6x +5 +4
y +4 = x^2 -6x +9
y +4 = (x -3)^2
y = (x -3)^2 - 4

vertex ( 3, -4) upwards facing like a bowl, because the "a" value is positive. So the vertex is the minimum, lowest point on the graph.


7 0
4 years ago
Find the distance between the following coordinates: I(-a,b), J(a,b)
olchik [2.2K]

Answer:

2a

Step-by-step explanation:

using distance formula:

√(x₂-x₁)² + (y₂-y₁)²

putting values,

√{a-(a)}² + {b-b}² = √ {a+a}² + 0²

= √(2a)² = √4a² = 2a

Hope this helps:)

8 0
3 years ago
Find a third-degree polynomial equation with rational coefficients that has roots –4 and 2 + i
ella [17]
If it has rational coefients and is a polygon
if a+bi is a root then a-bi is also a root

the roots are -4 and 2+i
so then 2-i must also be a root


if the rots of a poly are r1 and r2 then the factors are
f(x)=(x-r1)(x-r2)

roots are -4 and 2+i and 2-i

f(x)=(x-(-4))(x-(2+i))(x-(2-i))
f(x)=(x+4)(x-2-i)(x-2+i)
expand
f(x)=x³-11x+20
8 0
3 years ago
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