D- it is shifted to the right by pi/4
Answer:
![0.6 + \bar 0.47 = \frac{532}{495}](https://tex.z-dn.net/?f=0.6%20%2B%20%5Cbar%200.47%20%3D%20%5Cfrac%7B532%7D%7B495%7D)
Step-by-step explanation:
Given
![0.6 + \bar 0.47](https://tex.z-dn.net/?f=0.6%20%2B%20%5Cbar%200.47)
Required
Express as x/y
Let
![x = \bar 0.47](https://tex.z-dn.net/?f=x%20%3D%20%5Cbar%200.47)
This implies that:
--- (1)
Multiply by 100
--- (2)
Subtract 1 from 2
![100x - x = 99x](https://tex.z-dn.net/?f=100x%20-%20x%20%3D%2099x)
This gives
![47.4747 - 0.4747 = 47](https://tex.z-dn.net/?f=47.4747%20-%200.4747%20%3D%2047)
So:
![99x = 47](https://tex.z-dn.net/?f=99x%20%3D%2047)
Solve for x
This implies that:
becomes
![0.6 + \bar 0.47 = 0.6 + \frac{47}{99}](https://tex.z-dn.net/?f=0.6%20%2B%20%5Cbar%200.47%20%3D%200.6%20%2B%20%5Cfrac%7B47%7D%7B99%7D)
Express 0.6 as fraction
![0.6 + \bar 0.47 = \frac{6}{10} + \frac{47}{99}](https://tex.z-dn.net/?f=0.6%20%2B%20%5Cbar%200.47%20%3D%20%5Cfrac%7B6%7D%7B10%7D%20%2B%20%5Cfrac%7B47%7D%7B99%7D)
Take LCM and solve
![0.6 + \bar 0.47 = \frac{99*6+10*47}{990}](https://tex.z-dn.net/?f=0.6%20%2B%20%5Cbar%200.47%20%3D%20%5Cfrac%7B99%2A6%2B10%2A47%7D%7B990%7D)
Simplify
Answer:
Step-by-step explanation:
Collin initially have 14
Step-by-step explanation:
Let
x------> money that Brian had initially
y------> money that Collin had initially
we know that
x/y=7/2
solve for x
x=7/2y -------> equation A
y-39=y-4 ------> equation B
substitute equation A in equation B
7/2y-39=y-4
7/2y-y=39-4
5/2y=35
y=14
Answer:
see below PLEASE GIVE BRAINLIEST
Step-by-step explanation:
Fraction of 3rd piece: 4/12 or 1/3
Percents:
smallest:
3 ÷ 12 = 25%
Middle:
4 ÷ 12 = 33%
Largest:
5 ÷ 12 = 42%