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alekssr [168]
3 years ago
13

Find x (4x - 3) – ( x + 5) = 3(10 - x) please.....

Mathematics
2 answers:
mestny [16]3 years ago
6 0

Answer:

x = 4x^2 - 25

Step-by-step explanation:

x*4x - x*3 = 4xsquare - 3x

4x^2 - 3x - x + 5 = 3*10-3*x

4x^2 - 4x +5 = 30-3x

4x^2 +5 - 30 = -3x + 4x

4x^2 -25 = x

there fore , x =  4x^2 - 25  

Marina CMI [18]3 years ago
3 0

Answer:

x=14/3

Step-by-step explanation:

4x-3-x+5=30-3x

3x+2=30-3x

3x+3x=30-2

6x=28

x=28/6=14/3

x=14/3

<em>Hope this helps</em>

<em>please mark me as brainliest.</em>

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Answer:

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Step-by-step explanation:

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JulsSmile [24]
<h2>Part 1)</h2>

Let's analyze each part of the function:

FROM x = 0 TO x = 5:

We can find the equation of this line by using The Slope-Intercept Form of the Equation of a Line, that states:

The \ graph \ of \ the \ equation: \\ \\ y=mx+b \\ \\ is \ a \ line \ whose \ slope \ is \ m \ and \ whose \ y-intercept \ is \ (0, b)

So the y-intercept here is (0,4) and m=\frac{4}{5}, therefore:

\boxed{y=\frac{4}{5}x+4}

FROM x = 0 TO x = 5:

From the previous line, we know that at x=5 the output is:

y=\frac{4}{5}x+4 \\ \\ y=\frac{4}{5}(5)+4 \\ \\ y=4+4=8

So the point P_{1}(5,8) lies on both lines.

For this new line, the slope is m=-\frac{3}{5}

So, with the Point-Slope Form of the Equation of a Line we can find the equation of this other line:

The \ equation \ of \ the \ line \ with \ slope \ m \\ passing \ through \ the \ point \ (x_{1},y_{1}) \ is:\\ \\ y-y_{1}=m(x-x_{1})

So:

y-8=-\frac{3}{5}(x-5) \\ \\ y=8-\frac{3}{5}x+3 \\ \\ \boxed{y=-\frac{3}{5}x+11}

The graph is shown below.

<h2>Part 2)</h2>

The graph of the linear function f(x)=ax+b is a line with slope m=a and y-intercept at (0,b). From the items, we can assure that the following equations are linear functions:

\bullet 3y=2x-1.5 \ because \ y=\frac{2}{3}x-\frac{1}{2} \\ \\ \\ \bullet y=1 \ because \ y=m(0)+1 \\ \\ \\ \bullet 5(x+y)=-25 \ because \ 5x+5y=-25 \ \therefore 5y=-5x-25 \therefore y=-x-5

In conclusion, the other functions are nonlinear and they are:

\bullet \ y=x^2+3 \\ \\ \bullet \ y=x^3 \\ \\ \bullet \ y=12-x^2

7 0
3 years ago
Find the area of the convex polygon with vertices (0,5), (-1,2), (4,4), (-3,-4) and (2,0).
Afina-wow [57]

The area of the convex polygon is 43/2 square units

<h3>How to determine the area of the convex polygon?</h3>

The vertices are given as:

(0,5), (-1,2), (4,4), (-3,-4) and (2,0)

The area is then calculated as:

A = \frac 12(\left[\begin{array}{cc}x_1&x_2\\y_1&y_2\end{array}\right] + \left[\begin{array}{cc}x_2&x_3\\y_2&y_3\end{array}\right] + ....+\left[\begin{array}{cc}x_n&x\\y_n&y\end{array}\right] )

So, we have:

A = \frac12 * (|-1 * 5 - 2 * 0 + 0 * 4 - 5 * 4 + 4 * 0 - 4 * 2 + 2 * -4 - 0 * -3 -3 * 2 + 4 * 1|)

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A = \frac12 * (|-43|)

Remove the absolute bracket

A = \frac12 * 43

This gives

A = \frac{43}2

Hence, the area of the convex polygon is 43/2 square units

Read more about convex polygon at:

brainly.com/question/14522707

#SPJ1

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Step-by-step explanation:

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4 years ago
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max2010maxim [7]
<span><span>(10)</span><span>(3.26)</span></span><span>=<span>32.6

Your answer is in Bold.

~Good Luck~
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