Answer:
4√(3π) ft ≈ 12.28 ft
Step-by-step explanation:
The formulas for volume of a cone and a cylinder can be used to find the radius of the silo. Then the formula for the circumference of a circle can be used to find the circumference.
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Relevant formulas are ...
- V = πr²h . . . . . volume, cylinder with radius r, height h
- V = 1/3πr²h . . . . volume, cone with radius r, height h
- C = 2πr . . . . . . . . circumference of a circle with radius r
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<h3>radius from volume</h3>
The total volume of the silo is the sum of the volumes of a cylinder of height (15 -6) = 9 ft, and a cone of height 6 ft. Both have the same radius: r. The total volume is given as 132 ft³.
V = πr²h + 1/3πr²h' . . . . . . h = cylinder height, h' = cone height
132 ft³ = πr²(9 ft +1/3(6 ft)) = πr²(11 ft)
r² = 132 ft³/(11π ft) = 12/π ft²
r = √(12/π) ft = 2√(3/π) ft
<h3>circumference from radius</h3>
Then the circumference of the silo is ...
C = 2πr = 2π(2√(3/π)) ft = 4√(3π) ft ≈ 12.28 ft
The circumference of the base of the silo is 4√(3π), about 12.28 feet.
Answer:
none of the two graphs in the pic.
it should be one in the II quadrant
Step-by-step explanation:
the plus four means to move 4 to the left
the plus 2 means to move up 2
That would make the vertex in the II quadrant.
For 5 and 6 : 5 would be 144 when you put 3 in the position of the t . And 6 would be 1,024 when you put 8 where the t is .
The median would be: 7.9
and the mean would be:7.4714285714 (you are able to chop that down a bit if needed)
