f(h(x))= 2x -21
Step-by-step explanation:
f(x)= x^3 - 6
h(x)=\sqrt[3]{2x-15}
WE need to find f(h(x)), use composition of functions
Plug in h(x)
f(h(x))=f(\sqrt[3]{2x-15})
Now we plug in f(x) in f(x)
f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6
cube and cube root will get cancelled
f(h(x))= 2x-15 -6= 2 x-21
we have
Step 1
Eliminate the parenthesis
Step 2
Group terms that contain the same variable
Step 3
Combine like terms
therefore
the answer is
Answer:
Step-by-step explanation:
answer:
3x - 18 = 2y
5x - 6y = 14
5x - 3*(2y) = 14
5x - 3*(3x - 18) = 14
5x - 9x + 54 = 14
-4x = -40
x = 10
3*10 - 18 = 2y
30 - 18 = 2y
12 = 2y
y = 6
okay so you would first turn everything into fractions 2 3/4= 11/4 + 5/6
next you would change the denominators so they match 11/4 x 6 = 66/24
5/6 x 4 = 20/24
so then you would add 66/24 + 20/24 = 88/24 = 11/3
11/3 is your answer
hope this helps!
