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3 years ago

While loop project

Computers and Technology

1 answer:

ira [324]3 years ago

5 0

Answer: Change this however you'd like :)

Explanation:

for n in range(100):

print("priya")

print()

for n in range(10):

for i in range(10):

print("priya", end= " ")

print()

tempList = []

for n in range(1, 1001):

tempList.append(n)

print(sum(tempList))

print()

for n in range(1, 9):

for i in range(1, 9):

print(n*i)

print()

x = 100

while x != 0:

print(x)

x -= 1

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Human systems integration (hsi), a supportability issue that every program should consider, addresses such factors as accessibil

Tju [1.3M]

I guess the word in the blank is Standardization.

Human systems integration (HSI), a supportability issue that every program should consider, addresses such factors as accessibility, visibility, testability, and Standardization.

6 0

3 years ago

Write a program which asks the user to enter N numbers. The program will print out their average. Try your program with the foll

Likurg_2 [28]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variables

int n;

double average,sum=0,x;

cout<<"enter the Value of N:";

// read the value of N

cin>>n;

cout<<"enter "<<n<<" Numbers:";

// read n Numbers

for(int a=0;a<n;a++)

{

cin>>x;

// calculate total sum of all numbers

sum=sum+x;

}

// calculate average

average=sum/n;

// print average

cout<<"average of "<<n<<" Numbers is: "<<average<<endl;

return 0;

}

Explanation:

Read the total number from user i.e "n".Then read "n" numbers from user with for loop and sum them all.Find there average by dividing the sum with n.And print the average.

Output:

enter the Value of N:5

enter 5 Numbers:20.5 19.7 21.3 18.6 22.1

average of 5 Numbers is: 20.44

7 0

3 years ago

A*=++a/6+b++ 3 if a=3,b=4

Vinil7 [7]

Answer:

$a=22.5$

Explanation:

Given

$a*=++a/6+b++3$

Required

The result when $a=3$ and $b=4$

Analyzing the given instruction

a*=(++a)/(6)+(b++3)

Single out and solve the expressions in bracket

(++a) = a -- When the ++ operator appears before an operand, it is called pre increment. meaning that the operation will be done before the operand will be incremented.

So: in this case: ++a = a

$b++3 = b + 3$