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kirill115 [55]
2 years ago
8

6. Describe the outcome of the case Clark v. Arizona and why it was important.

SAT
1 answer:
densk [106]2 years ago
5 0
It Syllabus. Please please market me brainly
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6 0
2 years ago
15. For a random sample of n = 64, find the probability of a sample mean being
mart [117]

Answer:

0.9726

Explanation:

The computation of the probability of a sample mean is shown below:

P(\bar x < 24.3)

To find the probability first we have to determine the z score which is

z = \frac{\bar x - \mu_{\bar x}}{\sigma_{\bar x}} \\\\ = \frac{\bar x - \mu }{\frac{\sigma}{\sqrt{n} } } \\\\ = \frac{24.3 - 24}{\frac{1.25}{\sqrt{64} } }

= 1.92

Now probability is

P(\bar x < 24.3) \\\\= P(z < 1.92)

= 0.9726

Hence, the probability of the sample mean is 0.9726

We simply applied the above formulas to determined the probability of a sample mean and the same is to be considered

6 0
3 years ago
A 100-n weight is hung at the middle of a 4-m long horizontal clothesline. If the middle of the clothesline sags by 1 m, what is
Elena L [17]

The tension on each segment of the clothesline is :  110 N

<u>Given data : </u>

mass of object = 100 n  = 10 kg

Horizontal distance of clothesline = 4 m

middle of clothesline sag s by : 1m

<h3 /><h3>Determine the tension on each segment of clothesline</h3>

<u>First step</u> : calculate the horizontal angle made by the sagging

β = arctan ( 1 m / 2m )  ----- ( 1 )

  = arctan ( 0.5 )

  ≈ 26.57°

Note : Tension in th y axis ( Ty ) = Tsinβ

Therefore :

Tension on each segment can be calculated using the formula below

2Tsinβ - mg = 0

solve for T

T = mg / 2sinβ

  = ( 10 * 9.8 ) / 2 * sin 26.57°

  = 98 / 0.89

  = 110 N

Hence we can conclude that the tension on each segment of the clothesline is : 110 N

Learn more about Tension calculations : brainly.com/question/24994188

7 0
2 years ago
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